Proposition 4.2.3 ([Proposition 1.5, Fol99]).label Let $\curl{X_j}_{1}^{n}$ be topological spaces, $X=\prods{n}{j=1}X_{j}$, then:
- (1)
$\tprods{n}{j=1}\cali{B}_{X_j}\suf\cali{B}_{X}$.
- (2)
If $\curl{X_j}_{1}^{n}$ are separable, then $\tprods{n}{j=1}\cali{B}_{X_j}=\cali{B}_{X}$.
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