3.1 Generating Topologies

Definition 3.1.1 (Topological Space).label Let $X$ be a set, possibly empty. A topology on $X$ is a structure given by a collection $\tau\suf\mathcal{P}(X)$ satisfying:

  1. (O1)

    $\emp,X\in \tau$

  2. (O2)

    $\fall \curl{U_i}_{i\in I}\suf \tau,\cups{}{i\in I}U_{i}\in \tau$

  3. (O3)

    $\fall U,V\in \tau, U\cap V\in \tau$

The ordered pair $(X,\tau)$ (or just $X$ if $\tau$ is understood) is a topological space and elements of $\tau$ are open sets.

The elements of a topological space are points and $X$ is the underlying set of the topological space $(X,\tau)$. If $\tau\suf \tau'$ are topologies on $X$ then $\tau$ is coarser than $\tau'$ and $\tau'$ is finer than $\tau$.

Definition 3.1.2 (Closed Set).label Let $(X,\tau)$ be a topological space, then $A\suf X$ is closed if $A^{c}\in\tau$. We say $A\suf X$ is clopen if $A$ is open and closed.

Definition 3.1.3 (Seperation Axioms).label Let $(X,\tau)$ be a topological space, then we have the following separation axioms which $X$ might satisfy

  1. (T0)

    For any $x\neq y\in X$ there exists $U\in \tau$ such that either $y\nin U\ni x$ or $x\nin U\ni y$

  2. (T1)

    For any $x\neq y\in X$ there exists $U\in\tau$ such that $y\nin U\ni x$

  3. (T2)

    For any $x\neq y\in X$ there exists $U,V\in\tau$ such that $x\in U,y\in V$ and $U\cap V=\emp$

  4. (T3)

    $X$ is (T1) and for any $x\in X,A\suf X$ closed with $x\nin A$ there exists $U,V\in\tau$ such that $x\in U,A\suf V$ and $U\cap V=\emp$

  5. (T4)

    $X$ is (T1) and for any $A,B\suf X$ closed with $A\cap B=\emp$ there exists $U,V\in\tau$ such that $A\suf U,B\suf V$ and $U\cap V=\emp$

Definition 3.1.4 (Covering).label Let $X$ be a set and $A\suf X$. A collection $\curl{U_i}_{i\in I}$ is called a covering of $A$ if $A\suf\cups{}{i\in I}U_{i}$ and $U_{i}\suf X$ for each $i\in I$. A covering $\curl{U_i}_{i\in I}$ is said to be open (resp. closed) if $X$ is a topological space and all $U_{i}$ are open (resp. closed) in $X$. A covering $\curl{U_i}_{i\in I}$ is said to be (pairwise)disjoint if for each $i,j\in I$, $U_{i}\cap U_{j}=\begin{cases}\emp&i\neq j\\ U_{i}&i=j\end{cases}$. A subcover of a covering $\curl{U_i}_{i\in I}$ is a covering $\curl{V_j}_{j\in J}$ such that $J\suf I$ and $V_{j}=U_{j}$ for each $j\in J$ and $\curl{V_j}_{j\in J}$ is said to be finite if $J$ is finite.

Definition 3.1.5 (Base of Topology).label Let $X$ be a set then $\cali{B}\suf\cali{P}(X)$ is a base if it satisfies:

  1. (B1)

    For each $x\in X$ there exists $B_{x}\in\cali{B}$ such that $x\in B_{x}$ i.e. $\cali{B}$ is a covering of $X$

  2. (B2)

    If $x\in B_{1},B_{2}\in\cali{B}$ then there exists $B_{3}\in\cali{B}$ such that $x\in B_{3}\suf B_{1}\cap B_{2}$

then the topology generated by $\cali{B}$ defined as

\begin{align*}\tau(\cali{B})\define\curl{\cups{}{i\in I}B_i:\curl{B_i}_{i\in I}\suf \cali{B},I\text{ index set}}\end{align*}

is a topology on $X$. Suppose $X$ has a topology $\tau$ then we say $\cali{B}$ is a base for $\tau$ if $\cali{B}\suf \tau$ and

  1. (B’1)

    $\cali{B}$ satisfies (B1)

  2. (B’2)

    For each $x\in X, U\in\tau$ such that $x\in U$, there exists $B\in\cali{B}$ such that $x\in B\suf U$

in which case $\tau=\tau(\cali{B})$.

Proof. If $\cali{B}$ is a base then $\emp=\cups{}{\emp}\in\tau(\cali{B})$ and by (B1) $X=\cups{}{x\in X}B_{x}\in \tau(\cali{B})$ showing (O1). Observe that for any $\curl{B_i}_{i\in I},\curl{B_j}_{j\in J}\suf\cali{B}$ and $*\in \curl{\cap,\cup}$ we have

\begin{align*}\parens{\cups{}{i\in I}B_i}*\parens{\cups{}{j\in J }B_j}=\cups{}{i\in I}\cups{}{j\in J}B_{i}* B_{j}\end{align*}

by (B2) this observation shows (O3) and

\begin{align*}\cups{}{j\in J}U_{j}=\cups{}{j\in J}\cups{}{i\in I_j}B_{i,j}=\cups{}{(k,\el)\in \prods{}{j\in J}I_j\ti J }B_{k,\el(k)}\end{align*}

shows (O2).

Suppose now that $\cali{B}$ is a base for $\tau$ then by (O3) and $\cali{B}\suf \tau$ we have $\tau(\cali{B})\suf \tau$. For any $U\in \tau$ either $U=\emp\in\tau(\cali{B})$, or $U\neq \emp$. In which case by (B’2) for each $x\in U$ pick $B_{x}\in\cali{B}$ such that $x\in B_{x}\suf U$ then $U=\cups{}{x\in U }B_{x}\in \tau(\cali{B})$ as desired.$\square$

Definition 3.1.6 (Subbase of Topology).label Let $X$ be a set then $\cali{S}\suf\cali{P}(X)$ is a subbase if it is a covering of $X$. The smallest topology on $X$ containing $\cali{S}$ is given by

\begin{align*}\tau(\cali{S})\define\curl{\cups{}{i\in I }U_i:U_i\in\cali{B}(\cali{S})}=\caps{}{\text{topology }\tau\supf \cali{S}}\tau\end{align*}

where $\tau(\cali{S})$ is called the topology generated by $\cali{S}$ and

\begin{align*}\cali{B}(\cali{S})=\curl{\caps{}{j\in J }U_j:\curl{U_j}_{j\in J}\suf\cali{S},\abs{J}<\infty}\end{align*}

is a base for $\tau(\cali{S})$.

Proof. By construction $\cali{B}(\cali{S})$ is a base hence $\tau(\cali{S})$ is a topology by Definition 3.1.5 whose base is $\cali{B}(\cali{S})$. The inclusion $\tau(\cali{S})\suf \caps{}{\tau\supf \cali{S}}\tau$ follows from (O2) and (O3). On the other hand $\tau(\cali{S})$ is a topology that contains $\cali{S}$ so we are done.$\square$

Definition 3.1.7 (Intial Topology).label Let $X$ be a set, $\curl{(Y_i,\tau_i)}_{i\in I}$ be a family of topological spaces, and $\curl{f_i:X\to Y_i}_{i\in I}$ be a family of maps then there exists a topology $\tau$ on $X$ satisfying:

  1. (1)

    $f_{i}\in C(X;Y_{i})$ for each $i\in I$

  2. (U)

    $\tau$ is the coarsest topology on $X$ such that all $f_{i}$ are continuous

  3. (U’)

    For any topological space $Z$ and map $g:Z\to X$ we have $g$ is continuous if and only if $f_{i}\circ g:Z\to Y_{i}$ is continuous for each $i\in I$.

  4. (4)

    A subbase for $\tau$ is given by

    \begin{align*}\cali{S}=\curl{f_i\inv(U_i):U_i\in\tau_i,i\in i}\end{align*}

  5. (5)

    (1)+(U)$\iff$(U’)

called the intial/weak topology on $X$ generated by the maps $\curl{f_i}_{i\in I}$.

Proof. Let $\tau\define \tau(\cali{S})$ then by Definition 3.1.6

  1. (1)

    $\curl{f_i\inv(U_i):U_i\in\tau_i,i\in I}\suf \tau$ hence $f_{i}\in C((X,\tau);Y_{i})$ for each $i\in I$

  2. (U)

    If $\tau'$ is a topology on $X$ satisfying (1) then $\curl{f_i\inv(U_i):U_i\in\tau_i,i\in I}\suf \tau$ hence $\cali{S}\suf \tau'$ and so $\tau\suf\tau'$

  3. (U’)

    If $g$ is continuous then $f_{i}\circ g$ is continuous for each $i\in I$ since composition of continuous functions is continuous. Since finite intersections of subbasis sets form a basis and preimages commute with intersections, it suffices to check continuity of $g$ on a subbasis. Let $i\in I$ and $V\suf Y_{i}$ open then

    \begin{align*}g\inv(f_{i}\inv(V))=(f_{i}\circ g)\inv(V)\end{align*}

    is open in $Z$ by continuity of $f_{i}\circ g$ as desired.

  4. (4)

    Clear

  5. (5)

    Clear

$\square$

Definition 3.1.8 (Final Topology).label Let $X$ be a set, $\curl{(Y_i,\tau_i)}_{i\in I}$ be a family of topological spaces, and $\curl{f_i:Y_i\to X}_{i\in I}$ be a family of maps then there exists a topology $\tau$ on $X$ satisfying:

  1. (1)

    $f_{i}\in C(Y_{i};X)$ for each $i\in I$

  2. (U)

    $\tau$ is the finest topology on $X$ such that all $f_{i}$ are continuous

  3. (U’)

    For any topological space $Z$ and map $g:X\to Z$ we have $g$ is continuous if and only if $g\circ f_{i}:Y_{i}\to Z$ is continuous for each $i\in I$.

  4. (4)

    (1)+(U)$\iff$(U’)

called the final/strong topology on $X$ generated by the maps $\curl{f_i}_{i\in I}$.

Proof. Let $\tau\define \curl{U\suf X:\fall i\in I,f_i\inv(U)\in\tau_i}$ then $\tau$ is a topology since preimages commute with union and intersection. Furthermore

  1. (1)

    By definition $U\in\tau\implies f_{i}\inv(U)\in\tau_{i}$ for each $i\in I$ hence $f_{i}\in C(Y_{i};(X,\tau))$ for each $i\in I$

  2. (U)

    If $\tau'$ is a topology on $X$ satisfying (1) then for each $U\in\tau'$, $f_{i}\inv(U)\in\tau_{i}$ for all $i\in I$ so $U\in \tau$ so $\tau'\suf \tau$.

  3. (U’)

    If $g$ is continuous then $g\circ f_{i}$ is continuous for each $i\in I$ since composition of continuous functions is continuous. Let $i\in I$ and $V\suf Z$ open then

    \begin{align*}f_{i}\inv(g\inv(V))=(g\circ f_{i})\inv(V)\end{align*}

    is open in $Y_{i}$ by continuity of $g\circ f_{i}$ as desired.

  4. (4)

    Clear

$\square$

Definition 3.1.9 (Generated Topology).label Let $X$ be a topological space and $\s\suf\cali{P}(X)$ then $X$ is $\s$-generated if the topology on $X$ is the final topology generated by the inclusion maps $\curl{\iota_S:S\to X:S\in\s}$. If $\kappa\suf \cali{P}(X)$ is the collection of precompact sets of $X$ and $X$ is $\kappa$-generated then $X$ is compactly generated.

Definition 3.1.10 (Subspace Topology).label Let $(X,\tau_{X})$ be a topological space and $A\suf X$ be a subset then the subspace topology on $A$

\begin{align*}\tau_{A}=\curl{U\cap A:U\in\tau_X}\end{align*}

is the initial topology on $A$ with respect to the inclusion map $\iota:A\inj X$.

Proof. Observe

\begin{align*}\iota\inv(U)=\curl{a\in A:\iota(a)\in U}=\curl{a\in A:a\in U}=U\cap A\end{align*}

for any subset $U\suf X$ hence the same holds for $U\in\tau_{X}$.$\square$

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